MESHUGGAH-Obzen

1.5m : A= 3.1416 x 1.5² = 7m 2m V = 7x2 =14 m3 a.duu + v + w du + dv + dw u.v (v.du + u.dv) / ([164.2wpm x 0.48pbs]Fi)=PVQ([164.2wpm x 0.48pbs]Fi)=PVQv2 un n.un-1.uv v.uv-1.du + uv.ln(u).dveuStel = π.2002 = 3,14 . 40 000 = 125 600mm2 euea.u a.ea.u.du au au.ln(a)ln(u) u-1.du loga(u) u-1- tanh(u) / cosh(u) .cosh ( 2 . ) = cosh 2 + sinh 2 = 1 + 2 . sinh 2 = 2 . cosh 2 - 1sinh ( 2 . ) = 2 . sinh . cosh tanh ( 2 . ) = du 1 / sinh(u) - cotanh(u) / sinh(u) . du sinh-1(u) (u2+1)-½.du .loga(e).du uu uu.[1+ln(u)]sin(u)y = ax^2 + bx + c cos(u).du cos(u) -sin(u).du tan(u) 1 / cos2(u)cotan(u) - 1 / sin2(u) ([164.2wpm x 0.48pbs]Fi)=PVQ. du 1 / cos(u) tan(u) / cos(u) . du1 / sin(u) - cotan(u) / sin(u) . du sin-1(u) Stel = π.2002 = 3,14 . 40 000 = 125 600mm2 (1-u2)-½.du cos-1(u) -(1-u2)-½.du tan-1(u) (1+u2)-1.du. Vous avez deux heures.